x2-3xy-10y2-x+8y-2 因式分解啊

还有求证:若三角形的垂心和重心重合,则该三角形为正三角形
2024-12-22 13:15:00
推荐回答(2个)
回答1:

x2-3xy-10y2-x+8y-2
=(x-5y)(x+2y)-x+8y-2
=(x-5y+1)(x+2y-2)

回答2:

分解后应该是(x-5y+1)(x+2y-2)
过程如下:
x2-3xy-10y2-x+8y-2
=(x-5y)(x+2y) -x+8y -2
=(x-5y+1)(x+2y-2)