推荐回答（4个）
A.充入2mol SO3 由勒夏特烈原理，使反应逆向进行 SO3的体积分数变小
B. 充入2mol N2，压强增大，但各物质分压不变，所以无影响
C,充入0.5mol SO2和0.25mol O2，压强增大并增大反应物浓度，使反应正向进行，SO3的体积分数变大
D。由常识知此反映放热，升高温度使反应逆向进行 SO3的体积分数变小
E，很明显由勒夏特烈原理，压强增大使反应正向进行SO3的体积分数变大
此题不难，不会要多看书做题
高考题有的要难很多
A：因为压强不变，那么体积会变化。一开始相当于增加了SO2的量，然后会向反应正方向移动。由于无力过程大于化学过程，所以SO3浓度还是会下降。
B:冲入N2，SO2和O2的浓度都没有改变，所以SO3浓度不变。
C:体积不变，相当于加压了，会往气体体积减少的方向移动。SO2浓度增加
D和E：感觉像是凑数的答案- -你压缩了多少啊？升高了多少温度啊- -
F在哪里？
A,PV=nRT,不变
B,增加压强为无效压强，不变
C,充入二氧化硫和氧气，平衡抄三氧化硫方向移动，变大
D,反应放热，发生逆反应，减小
E,加压使平衡向正方向移动，变大
这是一个很简单的化学反应，首先要理解题意是要使“SO3的体积分数变大”的条件，
A、充入2mol SO3 肯定容器中的SO3的体积分数会变大，估计这个条件笔误，应该是充入2molSO2。所以答案里没有A。
B、充入2mol N2，SO3的体积分数只会变小。
C、充入0.5mol SO2和0.25mol O2后生产0.5molSO3，SO3的体积分数变大是肯定的。
D、升高温度所有物质的体积都在提高，SO3的体积分数不会变。
E、移动活塞压缩气体使压力增大，反应朝正方向发生，SO3的体积分数变大。
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