=(2x+2/3-5/3)/(3x+1)
=(2/3)(3x+1)/(3x+1) - 5/3(3x+1)
=2/3-5/[3(3x+1)]
(x^4+2x^3-5x^2-6x+1)/(x^2+x-6)
=[(x^4+x^3-6x^2)+ (x^3+x^2-6x+1)]/(x^2+x-6)
=x^2+(x^3+x^2-6x+1)/(x^2+x-6)
=x^2+x+1/(x^2+x-6)
=x^2+x+1/[(x-2)(x+3)]
Ls看来不懂多项式除法的原理
用多项式除法
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