已知X=2+根号3,Y=2-根号3,求X눀+3XY+Y눀

2024-12-16 14:49:11
推荐回答(3个)
回答1:

X²+3XY+Y²
=X²+Y²+3XY
=(X+Y)²-2XY+3XY
=(X+Y)²+XY
=16+4-3
=17

回答2:

X=2+根号3,Y=2-根号3
x+y=4
xy=1

X²+3XY+Y²
=(x+y)²+xy
=16+1=17

回答3:

17