已知x+4y-3z=0,4x-5y+2z=0,xyz不等于0,求3x2+2xy+z2⼀x2+y2的值。

2025-01-05 00:34:12
推荐回答(1个)
回答1:

x+4y-3z=0 (1)
4x-5y+2z=0 (2)
(1)*4-(2)得 21y=14z
y=2z/3
代入(1)得 x=z/3
(3x²+2xy+z²)/(x²+y²)
=z²(1/3+4/9+1)/[z²(1/9+4/9)]
=16/5