C语言制作简单的通讯录

2024-11-26 14:56:08
推荐回答(3个)
回答1:

主要是链表的操作,直接定义个结构体和指针的运用。

回答2:

/*编程建立一通讯簿,存放有姓名、电话号码、住址,然后对通信簿进行查找、添加、修改及删除。*/
#include
struct person
{
char name[8];
char tel[15];
char addr[50];
};

char filename[20];
FILE *fp;

void creat();
void output();
void search();
void append();
void modify();
void delete();

main()
{
int m;

creat();
while(1)
{
printf("\n\n添加,请按1");
printf("\n查找,请按2");
printf("\n修改,请按3");
printf("\n删除,请按4");
printf("\n输出,请按5");
printf("\n退出,请按0\n");
scanf("%d",&m);
if(m>=0&&m<=5)
{
switch(m)
{
case 1: append();
break;
case 2: search();
break;
case 3: modify();
break;
case 4: delete();
break;
case 5: output();
break;
case 0: exit();
}
printf("\n\n操作完毕,请再次选择!");
}
else
printf("\n\n选择错误,请再次选择!");
}
}

void creat()
{
struct person one;
long s1;

printf("\n请输入通讯簿名:");
scanf("%s",filename);
if((fp=fopen(filename,"w"))==NULL)
{
printf("\n不能建立通讯簿!");
exit();
}
fprintf(fp,"%-10s%-20s%-50s\n","姓名","电话号码","住址");
printf("\n请输入姓名、电话号码及住址(以0结束)\n");
scanf("%s",one.name);
while(strcmp(one.name,"0"))
{
scanf("%s%s",one.tel,one.addr);
fprintf(fp,"%-10s%-20s%-50s\n",one.name,one.tel,one.addr);
scanf("%s",one.name);
}
fclose(fp);
}

void output()
{
struct person one;

if((fp=fopen(filename,"r"))==NULL)
{
printf("\n不能打开通讯簿!");
exit();
}
printf("\n\n%20s\n","通 讯 簿");
while(!feof(fp))
{
fscanf(fp,"%s%s%s\n",one.name,one.tel,one.addr);
printf("%-10s%-20s%-50s",one.name,one.tel,one.addr);
}
fclose(fp);
}

void append()
{
struct person one;

if((fp=fopen(filename,"a"))==NULL)
{
printf("\n不能打开通讯簿!");
exit();
}
printf("\n请输入添加的姓名、电话号码及住址\n");
scanf("%s%s%s",one.name,one.tel,one.addr);
fprintf(fp,"%-10s%-20s%-50s\n",one.name,one.tel,one.addr);
fclose(fp);
}

void search()
{
int k=0;
char namekey[8];
struct person one;

printf("\n请输入姓名:");
scanf("%s",namekey);

if((fp=fopen(filename,"rb"))==NULL)
{
printf("\n不能打开通讯簿!");
exit();
}
while(!feof(fp))
{
fscanf(fp,"%s%s%s\n",one.name,one.tel,one.addr);
if(!strcmp(namekey,one.name))
{
printf("\n\n已查到,记录为:");
printf("\n%-10s%-18s%-50s",one.name,one.tel,one.addr);
k=1;
}
}
if(!k)
printf("\n\n对不起,通讯簿中没有此人的记录。");
fclose(fp);
}

void modify()
{
int m,k=0;
long offset;
char namekey[8];
struct person one;

printf("\n请输入姓名:");
scanf("%s",namekey);

if((fp=fopen(filename,"r+"))==NULL)
{
printf("\n不能打开通讯簿!");
exit();
}
while(!feof(fp))
{
offset=ftell(fp);
fscanf(fp,"%s%s%s\n",one.name,one.tel,one.addr);
if(!strcmp(namekey,one.name))
{
k=1;
break;
}
}
if(k)
{
printf("\n已查到,记录为:");
printf("\n%-10s%-18s%-50s",one.name,one.tel,one.addr);
printf("\n请输入新姓名、电话号码及住址:");
scanf("%s%s%s",one.name,one.tel,one.addr);
fseek(fp,offset,SEEK_SET);
printf("%ld",ftell(fp));
fprintf(fp,"%-10s%-20s%-50s\n",one.name,one.tel,one.addr);
}
else
printf("\n对不起,通讯簿中没有此人的记录。");
fclose(fp);
}

void delete()
{
int m,k=0,flag;
long offset1,offset2;
char namekey[8], valid[4];
struct person one;

printf("\n请输入姓名:");
scanf("%s",namekey);
if((fp=fopen(filename,"r+"))==NULL)
{
printf("\n不能打开通讯簿!");
exit();
}
while(!feof(fp))
{
offset1=ftell(fp);
fscanf(fp,"%s%s%s\n",one.name,one.tel,one.addr);
if(!strcmp(namekey,one.name))
{
k=1;
break;
}
}
if(k)
{
printf("\n已查到,记录为");
printf("\n%-10s%-18s%-50s",one.name,one.tel,one.addr);
printf("\n确实要删除,按1;不删除,按0:");
scanf("%d",&m);
if(m)
{
fseek(fp,offset1,SEEK_SET);
fprintf(fp,"%-10s%-20s%-50s\n","","","");
}
}
else
printf("\n对不起,通讯簿中没有此人的记录。");
fclose(fp);
}

回答3:

用一单连表就搞定了,很简单的啊