为什么硫酸分子中，硫是SP3杂化，与O有配位键，而不是SP3D2杂化？
推荐回答（5个）
这如果你学过VSEPR理论（价层电子对互斥理论）那应该是十分简单的，（你是搞竞赛的吗？我也是）
硫原子有6个价电子，在此理论中氧元素一般不看作提供电子（只得电子），而SO42-中带两个负电荷，所以(6+2)/2=4,所以硫原子是sp3杂化（为正四面体）。
而根据配位键的定义（即：共价键中电子对单方向提供而跟另一个原子（电子对接受体）共用所形成的化学键）用"A→B"表示。
所以其电子式为：
，，，，..
，，，: O :
，，.. ..， ..
H : O : S : O : H
，，.. .. ，..
，，，: O :
，，，，..
其结构式为：
，，，，O
，，，，↑
，，H-O-S—O-H
，，，，↓
，，，，O
今年不能复读了,如果你考的不理想的话,把你的联系方式留下(我找你),中国80%的学校让你选,但王牌专业有难度(像东南的土木工程),前提是你家出的起钱,这些学校普遍都在15万左右,你也别担心我骗你,到时拿到通知书再给钱
sp3d2杂化总共是6个轨道,硫酸分子除硫外貌似还有6个原子,所以问者才以为大家都可以以6个单键形式填充六个轨道凑成一个分子,可是有没有考虑过氧的轨道呢,形成单键后是不是还有点缺电子哇?
事实上氢是没有与硫直接成键的,也就是说硫酸分子中是没有H-S单键的。氢在分子中是以羟基形式与氧结合的。这样一来，硫的外围就只剩下4个原子/基团了，只能排出4个轨道，那么3d轨道就是不是可以不用动员了。根据硫的外层电子3s2 3p4以sp3杂化必然存在两个轨道由孤对电子占据，你予我取，形成配位键。
问者已经到杂化轨道的学习阶段了，貌似早就不该再理会电子式这个初级阶段的东东了哇。
电子式：
..
: O :
.. .. ..
H : O : S : O : H
.. .. ..
: O :
..
在百度知道中打电子式，累死我了。
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