4(x+2)^2=9(2x-1)^2
[2(x+2)]^2-[3(2x-1)]^2=0
[2(x+2)+3(2x-1)][2(x+2)-3(2x-1)]=0
(2x+4+6x-3)(2x+4-6x+3)=0
(8x+1)(7-4x)=0
x1=-1/8
x2=7/4
祝你学习进步O(∩_∩)O哈!
4(x+2)²=9(2x-1)²
4x²+16x+16=36x²-36x+9
32x²-52x-7=0
(4x-7)(8x+1)=0
4x-7=0或8x+1=0
x=7/4或x=-1/8
原方程可化为(2X+4)的平方=(6X-3)的平方
(6X-3+2X+4)*(6X-3-2X-4)=0
X=-1/8或X=7/4
4(X+2)²-9(2X-1)²=0
[2(x+2)+3(2x-1)][2(x+2)-3(2x-1)]=0
(8x+1)(-4x+7)=0
x=-1/8 x=7/4
4(x+2)=9(2x-1)或者4(x+2)=-9(2x-1),然后去加减法算呗