用“面向对象”的思想！用JAVA写“求解一元二次方程（要有复数解）”求大神认真作答！很重要的对我

public class Equation {
double a,b,c; //方程的系数
double x1,x2; //两个根
double r; //实部
double v; //虚部
int type; //0表示一个根，1表示两个实根，2表示两个复数的根
public Equation(double a,double b,double c){
this.a = a;
this.b = b;
this.c = c;
}
private double delta(){
return b*b-4*a*c;
}
public void calculate(){
double d = delta();
if(Math.abs(d) < 1E-5){
type = 0;
x1 = -b/(2*a);
x2 = x1;
}else if(d > 0){
type = 1;
x1 = (-b+Math.sqrt(d))/(2*a);
x2 = (-b-Math.sqrt(d))/(2*a);
}else{
type = 2;
r = -b/(2*a);
v = Math.sqrt(-d)/(2*a);
}
}
public void showResult(){
switch(type){
case 0:
System.out.println("方程只有一个实根，x1=x2="+x1);
break;
case 1:
System.out.println("方程有两个实根，分别是：x1="+x1+"\tx2="+x2);
break;
case 2:
System.out.println("方程有两个复数根，分别是："+r+"+"+v+"i,\t"+r+"-"+v+"i");
break;
}
}

public static void main(String[] args) {
Equation eq1 = new Equation(1,2,2); //对不同的系数a，b，c验算
eq1.calculate();
eq1.showResult();
Equation eq2 = new Equation(1,-2,1);
eq2.calculate();
eq2.showResult();
Equation eq3 = new Equation(1,6,5);
eq3.calculate();
eq3.showResult();
}

}

呵呵，楼上动作快啊，我也正想发同样的代码呢。