数学,简便计算问题 很简单 用递等式 随便做几道 ⼀除以 *乘

2024-12-18 21:14:38
推荐回答(2个)
回答1:

408×5÷8
=408÷8×5
=51×5
=255

38+62-38+62
=(38-38)+(62+62)
=62×2
=124

458-26-(74+58)
=(458-58)-(26+74)……打开括号里面变号
=400-100
=300

336÷(6×7)……打开括号里面变号,由乘变除
=336÷6÷7
=56÷7
=8

230÷(10÷4)
=230÷10×4
=23×4
=92

96×(3÷16)……打开括号不变号,括号前面是乘法,去掉括号后,不变号。
=96÷16×3
=6×3
=18

4505÷17÷5
=4505÷5÷17
=901÷17
=53

384×25÷8
=384÷8×25
=48×25
=12×(4×25)
=12×100
=1200

(54×24)÷(9×4)
=54×24÷9÷4
=(54÷9)×(24÷4)
=6×6
=36

236-(59+36)
=236-36-59……减法的性质,减去两个数,等于分别减去这两个数。
=200-59
=141

1847-1928+628-136-64
=1847-(1928-628)-(136+64)
=1847-1300-200
=1847-(1300+200)
=1847-1500
=347

1+2+3+4+5+…+2 009
=(1+2009)×2009÷2
=2010÷2×2009
=1005×2009
=1005×(2000+9)
=2010000+9045
=2019045

2+4+6+8+10+…+2 008
=(2+2008)×(2008÷2)÷2……(首项+末项)×项数÷2
=2010÷2×1004
=1005×1004
=1005×(1000+4)
=1005000+4020
=1009020

2008×20092009-20082008×2009……把20092009=2009×10001,20082008=2008×10001
=2008×2009×10001-2008×10001×2009……变一变,就简便
=0

回答2:

408*5/8=408/8*5=51*5=251
38+62-38+62=62+62=124
458-26-(74+58)=458-58-(26+74)=400-100=300
336/(6*7)=336/6/7=56/7=8
230/(10/4)=230/10*4=23*4=92
96*(3/16)=96/16*3=6*3=18
4505/17/5=4505/5/17=901/17=53
384*25/8=384/8*25=48*25=12*4*25=12*100=1200
(54*24)/(9*4)=(54/9)*(24/4)=6*6=36
236-(59+36)=236-36 -59=200-59=141
1847-1928+628-136-64=1847+600+28-1900-28-(136+64)=1847-1300-200=1847-1500=347
1+2+3+4+5+…+2 009=2009*(2009+1)/2=2009*2010/2=2009*1005=2009*1000+2009*5=2009000+10045=2019045
2+4+6+8+10+…+2 008=2*[1+2+...+1004]=1004*(1004+1)=1004*1005=1000*1005+4*1005=1005000+4020=1009020
2 008*20 092 009-20 082 008*2 009 = 2008*(20090000+2009) - (20080000+2008)*2009=2008*2009*10000+2008*2009-2008*10000*2009-2008*2009=0