∫xcos(x-1)dx
=∫cos(x-1)d(x^2/2)
=cos(x-1)*x^2/2-∫xd(cos(x-1)+c
=cos(x-1)*x^2/2+∫sin(x-1)d(x^2/2)+c
=cos(x-1)*x^2/2+∫sin(x-1)*x^2/2)+c
=cos(x-1)*x^2/2+sin(x-1)*x^2/2-∫xcos(x-1)dx+c
到此方程两边都有∫xcos(x-1)dx，移项得：
2∫xcos(珐讥粹客诔九达循惮末x-1)dx=cos(x-1)*x^2/2+sin(x-1)*x^2/2+c
化简得∫xcos(x-1)dx=√2/4[sin(x-1+π/4)]+c
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