2/(x+1)-1/(x-2)=02/(x+1)=1/(x-2)2(x-2)=x+12x-4=x+1x=5经检验x=5是原方程的根所以：原方程的根式x=5
去分母，两边同乘(x+1)(x-2)得2（x-2)-(x+1)=0x=3
2/（x+1)-1/(x-2)=02*(x-2)-(x+1)=02x-4-x-1=0x=5
