已知X-2Y=0,求X-Y/X+2Y除以X²-Y²/X²+4xy+4y²减2的值

2024-12-21 19:18:42
推荐回答(2个)
回答1:

x-2y=0
x=2y
(x-y)/(x+2y)÷(x^2-y^2)/(x^2+4xy+4y^2)-2
=(x-y)/(x+2y)*(x+2y)^2/(x+y)(x-y)-2
=(x+2y)/(x+y)-2
=(2y+2y)/(2y+y)-2
=4/3-2
=-2/3

回答2:

-2/3