初二数学,分式的运算 在线等!好的追加!

2025-02-06 06:03:56
推荐回答(2个)
回答1:

(x^2+xy)/(x^2-xy)÷(x+y)÷[xy/(x^2-xy)]
=(x^2+xy)/(x^2-xy)×[1/(x+y)]×[(x^2-xy)/xy]
=[(x^2+xy)(x^2-xy)]/[(x^2-xy)(x+y)xy]
=(x^2+xy)/[(x+y)xy]
=[x(x+y)]/[(x+y)xy]
=1/y

回答2:

上图的式子可化简为x分之一,只要你告诉结果就等于告诉x的值!