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230问答网 > 写出等差数列，1⼀5,3⼀5,1,7⼀5，··· 的通项公式，并求出数列的第11项

写出等差数列，1⼀5,3⼀5,1,7⼀5，··· 的通项公式，并求出数列的第11项

2025-03-27 14:57:02

推荐回答（2个）

回答1：

由an=a1+(n-1)d 的通项公式，d=2/5，所以an=1/5+(n-1)*2/5=2/5*n-1/5
所以a11=2/5*11-1/5=21/5=4又1/5

回答2：

an=(2n-1)/5,a11=21/5

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