arcsin(y^2⼀x)的一阶偏导

2024-12-21 09:06:31
推荐回答(1个)
回答1:

z=arcsin(y^2/x)
∂z/∂x = [1/√(1- (y^2/x)^2)] ( -y^2/x^2)
= -(y^2/x) [1/√(x^2- y^4)]

∂z/∂y = [1/√(1- (y^2/x)^2)] (2y/x)
=2y/√(x^2- y^4)