两道八下因式分解计算题(详细过程)在线等,急!!

2024-12-25 22:17:10
推荐回答(1个)
回答1:

(2^99-2^98)/(2^101-2^100)
=[2^98x(2-1)]/[2^98x(2^3-2^2)
=1/(8-4)
=1/4

100²/(251²-249²)
=100²/[(251+249)x(251-249)]
=10000/(500x2)
=10000/1000
=10