已知x+y=8,(x-y)²=4,求x²+y²的值、

2024-12-20 10:39:03
推荐回答(5个)
回答1:

x+y=8,
(x+y)2=64
x2+y2+2xy=64①

(x-y)2=4
x2+y2-2xy=4②

①+②= 2(x2+y2)=68
x2+y2=34

回答2:

x+y=8
(x+y)^2=x^2+y^2+2xy=64
(x-y)²=x^2+y^2-2xy=4
4xy=64-4
xy=15
x^2+y^2=2xy+4=2*15+4=34

回答3:

你好,冰雪闪舞ice

x²+y²
=[(x+y)²+(x-y)²]/2
=(8²+4)/2
=68/2
=34

回答4:

(x+y)²=64
(x+y)²-(x-y)²=4xy=64-4=60
XY=15
x²+y²=(x+y)²-2xy=64-30=34

回答5:

先把x+y平方再展开,将第二个展开,两式想加再除于2就行了