设x²+x-3=0,求x³+4x²+2008的值为多少?

2024-12-28 14:42:32
推荐回答(2个)
回答1:

x²+x-3=0
x²+x=3

x³+4x²+2008
=x(x²+x+3x)+2008
=x(3+3x)+2008
=3x²+3x+2008
=3*3+2008
=2017

回答2:

x³+4x²+2008=x(x²+x-3)+3(x²+x-3)+2017=2017