cos(A+π/4)=1/3,所以sin(A+π/4)=2√2/3,由cos(A+π/4)=1/3得√2/2cosA-√2/2sinA=1/3由sin(A+π/4)=2√2/3得√2/2sinA+√2/2cosA=2√2/3,此式减前一个式子得√2sinA=(2√2-1)/3sinA=(4-√2)/6