∫xcos눀xdx

2024-12-20 21:02:39
推荐回答(2个)
回答1:

∫xcos²xdx=∫x(1+cos2x)/2dx=1/2(∫xdx+∫xcos2xdx)
=1/2(1/2x²+∫xcos2xdx)
=1/2(1/2x²+1/2∫xdsin2x)
=1/2(1/2x²+1/2(xsin2x-∫sin2xdx))
=1/2(1/2x²+1/2xsin2x+1/4cos2x)+C

回答2: