今年小强和爸爸两人的年龄和是38岁,三年就要小强比爸爸小26岁,今年爸爸和小强各多少岁?

2025-02-12 02:26:50
推荐回答(5个)
回答1:

解: 设小强今年的年龄是y岁,根据题意可知,爸爸的年龄应该是(38-y)岁。三年后,小强的年龄比爸爸小26岁。那么由题意可列下面方程
y+3=(38-y)+3-26
y+3=38-y+3-26
移项 得
2y=12
y=6(岁)
答: 今年爸爸和小强的年龄分别是32岁、6岁。
答题完毕。

回答2:

三年前小强比爸爸小26岁,也就是说两个人的年龄差是26岁。
做法一:
(38-26)÷2
=12÷2
=6(岁)
38-6=32(岁)
做法二:
(38+26)÷2
=64÷2
=32(岁)
38-32=6(岁)
答:今年爸爸32岁,小强6岁。

回答3:

高兴为你详细解答

请采纳,谢谢!!

根据条件, 三年后小强比爸爸小26岁 .

不管多少年后, 两人的年龄差都是不变的, 所以今年小强也比爸爸小26岁。

又已知两人的年龄和是38岁,

列算式解,

小强的年龄=(38-26)÷2=6 岁

爸爸的年龄= 38-6 = 32岁

方程解, 设小强今年x岁, 爸爸 (38-x)岁.

x+26= 38-x

x+x= 38-26= 12

解得 x=6, 38-x=32

回答4:

爸爸32岁,小强6岁。假设今年爸爸是a岁小强是b岁
a+b=38 3年后爸爸比小强大26岁
a-b=26 得出a等于32岁
b等于6岁

回答5:

这个题是二元一次方程,切小强年龄为x,爸爸年龄是y,x+y=38,y-x=26,得出结果是小强6岁,爸爸32岁

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