(1)发光二极管正常工作时UL=2.0V,由图象可知串联电路的电流:I=IL=20mA=0.02A,定值电阻两端的电压:UR=U-UL=12V-2V=10V,R= U I = 10V 0.02A =500Ω,(2)由题意可知,采用的电源电压为3V,故为了安全和准确,电压表应选取D,3V的量程;由图可知,最大电流约为40mA,故电流表应选F;故选D,F;故答案为:(1)串联,500Ω (2)D,F