一个圆柱形水桶可装水六十二点八升,底面直径是四厘米,这个水桶的高是多少分米?

2025-03-31 03:55:57
推荐回答(5个)
回答1:

分析:先求出圆柱形水桶的底面积,再根据高=圆柱体体积(πr²h)÷底面积即可解答.

解:62.8升=62.8立方分米

4÷2=2(分米)

62.8÷(3.14×22)
=62.8÷12.56
=5(分米)
答:这个水桶的高是5分米.

回答2:

62.8升=62.8立方分米
4厘米=0.4分米
底面半径:0.4÷2=0.2分米
底面积:3.14ⅹ0.2ⅹ0.2=0.1256平方分米
水桶高:62.8÷0.1256=500分米
水桶高500分米。

回答3:

有可能是四厘米,也有可能是62厘米,也有可能是70厘米,也有可能是30厘米,也有可能是100毫米

回答4:

62.8升=62.8立方分米,底面直径是4厘米=0.4分米,半径为0.2分米,则高h=62.8÷3.14÷0.2^=500分米

回答5:

1升是1000毫升。体积的计算公式为底面积×高,底面积为πr²=3.14×(40÷2)²=1256毫米²。62800=1256×高h。解得高h=50毫米=5分米。

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