重利加速度 g = GM/R^2GMm/(R+h)^2 = mω^2*(R+h) ω=2π/Tsg*[R/(R+h)]^2 = 4π^2/Ts^2*(R+h)得到 Ts = √[ 4π^2*(R+h)^3/(g*R^2) ]扫描角 Ts/T*360度
补充一句。求出扫描角后再乘以地球半径R才得弧长。结果是4π²/T*√[(R+h)³/g]
