问:有关无机化学的计算题,求大神能够解答,要详细解题过程在浓度为0.06mol⼀L AgNO3溶液

2024-12-27 02:36:14
推荐回答(1个)
回答1:

Ag+ + 2NH3 <===> Ag(NH3)2+ K稳=1.7*10^7
AgCl <===> Ag+ + Cl- Ksp=1.7*10^-10
Ag(NH3)2+ + Cl- <===> Ag+ + 2NH3 K=1/(K稳*Ksp)=346.02
0.06 0.01 x
x^2/(0.06*0.01)=K=346.02
x=0.46