八年级因式分解题

2024-12-29 04:56:56
推荐回答(3个)
回答1:

解法如下:
x2(a-1)+y2(1-a)
=(a-1)(x2-y2)
=(a-1)(x+y)(x-y)

回答2:

太简单了,例把a-2看成-2-1就可以提取公因式了

回答3:

x²(a-1)+y²(1-a)=x²(a-1)-y²(a-1)=(a-1)(x²-y²)=(a-1)(x+y)(x-y)
-x³+x²-1/4x=x(-x²+x-1/4)