已知a^2-a-4=0,求a^2-2(a^2-a+3)-1⼀2(a^2-a-4)-a的值

2024-12-23 04:05:38
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回答1:

a^2-2(a^2-a+3)-1/2(a^2-a-4)-a
=a^2-2((a^2-a-4)+7)-(1/2)*0-a
=a^2-2*7-a
=(a^2-a-4)-10
=-10