1⼀(1+2)+1⼀(1+2+3)+……+1⼀(1+2+3……+100)怎么算?

请问是怎么算的?
2024-12-21 20:29:02
推荐回答(3个)
回答1:

因为
1+2=2*3/2
1+2+3=3*4/2
......
1+2+3+4+......+100=100*101/2
所以
1/(1+2)+1/(1+2+3)+1/(1+2+3+4)+...+1/(1+2+3+4+......+100)
=2(1/2 -1/3) +2(1/3-1/4)+......+2(1/100-1/101)
=2*(1/2-1/101)
=99/101

回答2:

1/(1 2) 1/(1 2 3) … 1/(1 2 3… 100)
=(1/2 1/3)*2 (1/3 1/4)*2 … (1/100/1/101)*2
=(1/2 1/3-1/3 1/4-1/4 … 1/100-1/101)*2
=(1/2-1/101)*2
=1-2/101
=99/101

回答3:

=101