(1)S1、S2闭合,S3断开时,只有电阻R1接入电路,∵I= U R ,∴电阻R1= U1 I = U I = 6V 0.5A =12Ω;(2)S1、S3断开,S2闭合时,两电阻串联,电压表测电阻R2两端电压,U2=UV=4V,U1′=U-U2=6V-4V=2V,电路电流I′= U1′ R1 = 2V 12Ω = 1 6 A,∵I= U R ,∴电阻R2= U2 I′ = 4V 1 6 A =24Ω;故答案为:12;24.