y=sin²(x)sin(x²),这样写好计算,用链式法则
dy/dx=sin(x²)*d(sinx)²/d(sinx)*d(sinx)/dx+sin²(x)*d[sin(x²)]/d(x²)*d(x²)/dx
=sin(x²)*(2sinx*cosx)+sin²(x)*[cos(x²)*2x]
=sin(x²)*(sin2x)+sin²(x)*[2xcos(x²)]
=sin2xsin(x²)+2xsin²(x)cos(x²)
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