怎么获取通过servlet 文件上传的文件

一、服务器端Servlet代码：
import javax.servlet.ServletException;
import javax.servlet.annotation.MultipartConfig;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.Part;
import java.io.IOException;

@WebServlet(name = "UploadTestServlet",urlPatterns = {"/upload"})
//下面的注解中location的值为上传的文件的临时存放位置
@MultipartConfig(location = "D://uploadtest")
public class UploadTestServlet extends HttpServlet {
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
System.out.println(request.getParameter("uploaderName"));

Part part=request.getPart("file"); //通过表单中的name属性获取表单域中的文件
part.write("D://uploadtest//aaa.txt"); //将文件移动到特定的磁盘路径

String fname=part.getSubmittedFileName();
System.out.println("文件名："+fname);
}

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

}
}

二、浏览器端HTML代码
版本1、普通表单提交
Servlet 通过表单上传文件和获取表单数据的最简单方式