将函数f(x)=ln(1-x^5)⼀(1-x) 展开成麦克劳林级数

是ln[(1-x^5)⼀(1-x)]
2025-01-24 03:52:04
推荐回答(1个)
回答1:

f(x)=1/(5-x)=(1/5){1/[1-(x/5)]}=(1/5){1+(x/5)+(x/5)²+···+(x/5)^n+····},成立区间(|x|