有没有大神知道这个题怎么做啊?(PS: 步骤请写简单点 太复杂了看不懂׶)

2025-02-10 22:20:02
推荐回答(2个)
回答1:


△相似,

回答2:

令FC与DG交点为P,正方形DEFG边长为m:
PD/FE=CD/CE
PD/m=15/(15+m)
PD=15m/(15+m)
PA = 15-PD
= 15-15m/(15+m)
= (225+15m-15m)/(15+m)
= 225/(15+m)
S△ACF= S△APF+S△APC
= 1/2*AP*FG + 1/2*AP*AB
= 1/2*AP*(FG+AB)
= 1/2*225/(15+m)*(m+15)
= 225/2
= 112.5