设公比为qa1+a2+a3=6 a2+a3+a4=q(a1+a2+a3)=-3 所以q=-1/2 a1+a2+a3=a1+a1*q+a1*q^2=a1(1+q+q^2)=3*a1/4=6a1=8a3=a1*q^2=2a3+a4+a5+a6+a7=a3*(1+q)+q^4(a1+a2+a3) =1+3/8=11/8
11/8