cos二分之三π+α=cos(-2π+二分之三π+α)=cos(α-π/2)=sin(π-α)=sinαcos(3π-α)=cos(π-α)=-cosα
cos(2π/3 +α)=cos(2π/3).cosα - sin(2π/3).sinα=-(1/2)cosα - (√3/2)sinα cos(3π +α)=cos(2π +(π +α))=cos(π +α)=-cosα
cosa -cosa