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C语言，已知一个正整数n，输出n阶的实心菱形

2025-03-15 01:09:32

推荐回答（3个）

回答1：

#include
int main(void)
{
int i,n,z,m,k,l;
scanf("%d",&n);
for(i=0;i {
for(k=0;k printf(" ");
for(l=0;l<=i;l++) //同理设置输出*的个数
printf("* ");
printf("\n"); //执行换行
}
for(i=n-1;i>=0;i--) //设置下面图形比上面少了一行所以是 n-1
{
for(k=0;k printf(" ");
for(l=0;l<=i;l++) //同样设置*的数目
printf("* ");
printf("\n"); //同样换行
}
return 0;
}
应该可以看懂了不懂再问吧嘿嘿

回答2：

#include 

int main()
{
    int i, j, n;
    printf("请输入n: ");
    scanf("%d", &n);
    
    /*
     * 以下注释假设n=3进行分析
     */
    
    // 菱形上半部
    for (i=0; i        for (j=0; j            printf(" ");
        }
        for (j=0; j<2*i+1; j++) { //右边的星号, 1-3-5递增
            printf("*");
        }
        printf("\n"); //下一行
    }
    // 菱形下半部
    for (i=1; i        for (j=0; j            printf(" ");
        }
        for (j=0; j<2*(n-i)-1; j++) { //右边的星号, 3-1递减
            printf("*");
        }
        printf("\n"); //下一行
    }
}

回答3：

/*菱形星号组成，我才发现我没做过*/
#include
#include
int main(void)
{
	int i,n;
	char *str=NULL;
	/*定义一个活动长度的字符串*/
	scanf("%d",&n);
	/*输入n*/
	str=(char*)malloc(sizeof(char)*(2*n));
	/*为字符串设定长度*/
	for(i=0;i<2*n-1;i++)
		str[i]='*';
	str[i]='\0';
	/*为字符串付值，是一串星号，长度是2n-1*/
	for(i=1;i<=2*n-1;i++)
		printf("%*.*s\n",i<=n?n+i:n*3-i,i<=n?i*2-1:n*4-i*2-1,str);
	/*用格式输出控制输出*/
	free(str);
	/*释放指针*/
	return 0;
}

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