求定积分,要详细过程,谢谢

2025-01-24 08:49:31
推荐回答(1个)
回答1:

令2x+1=t
x的上下限为(0,-1/2)
当x=0时,t=1
当x=-1/2时,t=0
所以积分上下限变为(1,0)
x=(1-t)/2
dx=-1/2
dt
所以原式=
∫(1,0)
t^99
(-1/2)
dt
=(-1/2)∫(1,0)
t^99
dt
=(-1/2)t^100/100
+C
|
(1,0)
=-1/200-0
=-1/200