sin(π⼀8)四次方+cos(π⼀8)四次方等于?过程

2024-12-17 05:20:58
推荐回答(1个)
回答1:

=[sin(π/8)二次方+cos(π/8)二次方]^2 - 2·sin(π/8)二次方·cos(π/8)二次方
=1 - (1/2)·sin(π/4)二次方
=1 - (1/2)·(√2/2)二次方
=3/4