6⼀5-(3⼀2-2⼀3)怎样脱式计算?

2024-12-12 00:33:58
推荐回答(1个)
回答1:

6/5-(3/2-2/3)
=(1+1/5)-(1+1/2-2/3)
=1+1/5-1-1/2+2/3
=(1-1)+(2/3-1/2)+1/5
=0+(4/6-3/6)+1/5
=1/6+1/5
=5/30+6/30
=11/30