初二物理声速问题

2024-11-24 14:16:24
推荐回答(4个)
回答1:

因为铁管的长度是一定的,为1000米,在空气中传播的速度也是知道的,为340米/秒,则需要的时间为1000/340,因为声音在介质中的传播速度,和介质是有关系的,如果介质不一样,则传播速度是不一样的,设在铁管中的传播速度为X,则在铁管中到达另一端的时间为1000/X,他们的间隔时间是知道的,
为2.75秒。
则得到等式为:1000/340-1000/X=2.75,得到X=5230。
即声音在铁中的速度是5230m/s

回答2:

另光在铁管中传播速度为XM/s,光在空气中的传播速度为Ym/s,则,由题知:第一次听到声音的时间为t1=1000/x,第二次听到声音的时间t2=1000/y,t1-t2=2.75,因y时确定的数,所以根据以上公式的联合就可得到x

回答3:

长度等于速度乘时间,听到二次的声音差是路程与速度的比值之差,知道长度、声速、时间差,就可求出声音在铁管中的速度了。声速这指声音在空气中的速度。

回答4:

声音沿着空气传播所用的时间
t1=s/v1=1000m/340m/s≈2.94s
声音沿着铁管传播所用的时间
t2=t1-t=2.94s-2.75s=0.19s
声音在铁管中的传播速度
v2=s/t2=1000m/0.19s≈5263m/s

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