一道高一化学题…

2025-01-04 04:00:15
推荐回答(2个)
回答1:

(1)设1体积为1L,
700L
--------
22.4L/MOL
C====_______________________________________======0.018367346mol/L
1000cm3 X 1g/cm3 + 700L
---------X 17g/mol
22.4L/mol
-------------------------------------
0.9g/cm3

(2) 700L
----------X17g/MOL
22.4L/MOL
w=====—————————————————————===34.69%
1000cm3 x 1g/cm3 + 700L
----------- X17g/MOL
22.4L/MOL

回答2:

设水的体积为1ml
则NH3的体积为700ml
气体摩尔体积(标况下)=22.4L/mol
所以n(NH3)=0.7/22.4
1cm^3=1ml
所以0.9g/cm^3=0.9g/ml
水的质量为0.9*1.0=0.9g
NH3的质量为0.7/22.4*17=0.53125g
所以溶液质量为0.9+0.53125=1.43125g
溶液体积为1.43125/0.9
则,c(NH3)=(0.7/22.4)/(1.43125/0.9)=0.019650655021834061135371179039301mol/L
=0.02mol/L
质量分数为0.53125/1.43125=0.37117903930131004366812227074236=37.1%
打得很辛苦,加点分吧