球从高处自由下落,每次接触地面后弹起的高度是前一次下落高度的5分之2.如果球从125米高处落下,

那么第三次弹起的高度是多少米?(要写过程)
2024-12-19 17:48:42
推荐回答(4个)
回答1:

第一次弹起高度125*2/5;
第二次弹起高度(125*2/5)*2/5;
第三次弹起高度[(125*2/5)*2/5]2/5,即125*8/125=8米;
……
第n次弹起高度125*(2/5)^n。

这个球什么时候弹不起来呢?
《庄子》曰:一尺之棰,日取其半,万事不竭。

回答2:

1-2/5=3/5
125*(3/5)*(3/5)*(3/5)=27米

回答3:

是12米

回答4:

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