1⼀2000*2001+1⼀2001*2002+1⼀2002*2003+...+1⼀2007*2008=?

2024-12-16 17:27:30
推荐回答(2个)
回答1:

解:由公式1/n(n+1)=1/n-1/(n+1)得知,原式=(1/2000-1/2001)+(1/2001-1/2002)+(1/2002-1/2003)+(1/2003-1/2004)+(1/2004-1/2005)+(1/2005-1/2006)+(1/2006-1/2007)+(1/2007-1/2008)=1/2000-1/2008=1/502000

回答2:

1634