1+2+3+4+...98+99+100,用两种方法解决?

2025-03-16 04:40:21
推荐回答(5个)
回答1:

第一种方法,

=(1+99)+(2+98)+(3+97)+.....+(49+51)+50+100

=100×49+50+100

=4900+150

=5050

第二种方法,公式法,

=(1+100)×100÷2

=101×100÷2

=10100÷2

=5050

乘法:

①求几个几是多少;

②求一个数的几倍是多少;

③求物体面积、体积;

④求一个数的几分之几或百分之几是多少。

除法:

①把一个数平均分成若干份,求其中的一份;

②求一个数里有几个另一个数;

③已知一个数的几分之几或百分之几是多少求这个数;

④求一个数是另一个数的几倍。

回答2:

第一种方法,
=(1+99)+(2+98)+(3+97)+.....+(49+51)+50+100
=100×49+50+100
=4900+150
=5050
第二种方法,公式法,
=(1+100)×100÷2
=101×100÷2
=10100÷2
=5050

回答3:

等差数列公式,直接得到5050

回答4:

我主要提供一个比较简便的方法,就是把第一个和最后一个加起来,然后第二个跟倒数第二个数字加起来,这样加每个加起来的数字都为101,然后100个数字就会有50组也就是101*50也就是结果了。另一种可以把100单独拎出来看,也就是只加到99,按照同样上面那种方法中间会剩一个数字,也就是50,那么也就是有49组100,再加上多出来的50和100,两个方法答案相等

回答5:

1,一个数字一个数字的加起来。2,1+100,再乘以50。

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