设A,P阶可逆方阵,下列矩阵中必与矩阵A具有相同的特征值

2025-03-28 12:54:35
推荐回答(3个)
回答1:

与矩阵A具有相同的特征值的矩阵是:P⁻¹AP

A⁻¹与A的特征值关系是1/λ,A*与A的特征值关系是|A|/λ,Aᵐ与A的特征值关系是λᵐ,而kA与A的特征值关系是kλ,所以与矩阵A有相似特征值的矩阵是P⁻¹AP的矩阵,即与矩阵A相似的矩阵。

扩展资料

相似矩阵的判定:

1、首先判断是否有相同的行列式和迹、秩、以及特征值。

2、判断矩阵是否可以对角化,利用结论两个可对角化的矩阵相似的充要条件是有相同的特征值。如果所给矩阵都不可以对角化。

3、判断其对应的特征矩阵的秩是否相等。相似矩阵具有相同的特征值,反之不成立。但是当两个矩阵都是可对角化矩阵时,这时有相同的特征值就可以推出两矩阵是相似的。

回答2:

P的逆*A*P

回答3:

p阶与A相似矩阵。

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