初三物理比热容计算题

2024-11-20 09:07:23
推荐回答(5个)
回答1:

200G=0.2KG 80G=0.08G Q吸=Q放则由公式Q=CM乘变化的温度得4.2乘1000乘0.08=0.6048乘1000即0.2乘18乘铅的比热容=0.6048乘1000即得铅的比热容为0.168乘1000

回答2:

水的温度是12到18比热容是420,
所以Q=CMΔT=4200X0.08X(18—12)=2016J(吸热量)
所以铅放热201.6J
Q=CMΔT 2016=CX0.2X(98-18)=126J/KG,C

回答3:

(1)、5×1010kg煤完全燃烧将放出的热量:Q=mq=5×10^10kg×2.9×10^7J/kg=1.45×10^18J
(2)、V=m/p=1.2×10^10kg
/
(1.98kg/m^3)=6.1×10^9m^3
(3)设火力发电站在单位时间内产生的电能为E,它在这段时间内所消耗的燃料完全燃烧所产生的热量为Q,则火力发电站的效率为E/Q。

回答4:

水吸收的热量
Q吸=C水m水Δt水
金属放出的热量
Q放=C金m金Δt金
则C水m水Δt水=C金m金Δt金
4200*420*(20-12)=C金*200*(100-20)
金属的比热容为
C金=882J/kg℃

回答5:

Q吸=Q放=Cmt,C0.2(100-20)=(4.2*10^3)0.42(20-12),2*8C=8*42*42,2C=42*42,比热容C=21*42=882j/(g•c)=0.882*10^3j/(kg•c)。

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