(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)=?

怎么计算?要过程...只有答案的闪...
2024-12-20 04:23:32
推荐回答(1个)
回答1:

(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
=(3-1)(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)/2
=(3^2-1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)/2
=(3^4-1)(3^4+1)(3^8+1)(3^16+1) /2
=(3^8-1)(3^8+1)(3^16+1)/2
=(3^16-1)(3^16+1)/2
=(3^32-1)/2