答:a^2+b^2=5ab=1解:(a+b)^2=a^2+b^2+2ab(a-b)^2=a^2+b^2-2ab(a+b)^2=a^2+b^2+2ab=7......(1)(a-b)^2=a^2+b^2-2ab=3......(2)(1)+(2),得2*(a^2+b^2)=10a^2+b^2=5(1)-(2),得4ab=4ab=1
ab=1