推荐回答(5个)
根据你的反馈,回复如下:
假如进程名为12345678.exe,则可以分三步解决:
一、定义数组a(),然后枚举所有进程,找出进程名为12345678.exe的进程,并将其ID存入数组a()中
二、枚举所有窗口,取得对应的进程ID,然后与数组a()中的ID进行比较,若处于可见状态且ID相同,则将该数组元素置为空。
三、循环检验数组a(),如ID不为空,则终止此进程。
能搞定,但是这点分数说实在话不够贴代码的哦。实在是抱歉了。
我个人推荐你用第一个方法。
第二个也行,但是不确定因素太多了。
找到进程名就已经是抓到小辫子了 hoho
Option Explicit
Private Declare Function FindWindow Lib "user32" Alias "FindWindowA" (ByVal lpClassName As String, ByVal lpWindowName As String) As Long
Private Declare Function IsWindowVisible Lib "user32" (ByVal hwnd As Long) As Long
Private Const WM_CLOSE = &H10
Private Declare Function SendMessage Lib "user32" Alias "SendMessageA" (ByVal hwnd As Long, ByVal wMsg As Long, ByVal wParam As Long, lParam As Any) As Long
Private Sub Command1_Click()
Dim hwnd As Long
hwnd = FindWindow(vbNullString, "abcdefg")
If hwnd = 0 Then
MsgBox "程序未运行"
ElseIf IsWindowVisible(hwnd) = 0 Then SendMessage hwnd, WM_CLOSE, 0, 0
End If
End Sub
你多按几下command
呵呵,所有系统服务进程的窗口都隐藏的,你也要结束?
LZ 如果找不到满意答案的话 建议不要再提高分数啦 因为我以前提过100分
竟然回答的人都没有一个 - -
百度这个很不好啊 为什么不能没有人回答分数回返呢?
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